35x^2+41x+12=0

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Solution for 35x^2+41x+12=0 equation:


Simplifying
35x2 + 41x + 12 = 0

Reorder the terms:
12 + 41x + 35x2 = 0

Solving
12 + 41x + 35x2 = 0

Solving for variable 'x'.

Factor a trinomial.
(3 + 5x)(4 + 7x) = 0

Subproblem 1

Set the factor '(3 + 5x)' equal to zero and attempt to solve: Simplifying 3 + 5x = 0 Solving 3 + 5x = 0 Move all terms containing x to the left, all other terms to the right. Add '-3' to each side of the equation. 3 + -3 + 5x = 0 + -3 Combine like terms: 3 + -3 = 0 0 + 5x = 0 + -3 5x = 0 + -3 Combine like terms: 0 + -3 = -3 5x = -3 Divide each side by '5'. x = -0.6 Simplifying x = -0.6

Subproblem 2

Set the factor '(4 + 7x)' equal to zero and attempt to solve: Simplifying 4 + 7x = 0 Solving 4 + 7x = 0 Move all terms containing x to the left, all other terms to the right. Add '-4' to each side of the equation. 4 + -4 + 7x = 0 + -4 Combine like terms: 4 + -4 = 0 0 + 7x = 0 + -4 7x = 0 + -4 Combine like terms: 0 + -4 = -4 7x = -4 Divide each side by '7'. x = -0.5714285714 Simplifying x = -0.5714285714

Solution

x = {-0.6, -0.5714285714}

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